Create 1021(회전하는큐).java#34
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1. 현재 target의 인덱스(idx)를 챶움.
2. 왼쪽 회전거리 = idx
오른쪽 회전 거리 = deque.size() - idx
3. 더 짧은 거리로 회전 후 pop
O (N * m) // 제약조건이 N < 50 이므로 충분히 빠름.
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아 문제 접근 방식 너무 훌륭하네요..... 저도 이런식으로 좀... 적으면서 해야겠어요 |
yu-heejin
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Aug 10, 2025
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LinkedList로 dequeue쓸 수 있는거 배우고 가요 ~~
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우왓! 저랑 똑같은 문제! 저 사실 gpt한데 제일 쉬운 문제 추천해달라고 해서 ㅋㅋㅋㅋ 채찍피티와 함께 풀었씁니다.. |
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O (N * m) // 제약조건이 N < 50 이므로 충분히 빠름.